SHMMedium
Question
Two particle executes S.H.M of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, each time their displacement is half of their amplitude. The phase difference between them is : -
Options
A.30o
B.60o
C.90o
D.120o
Solution
x = A sin ωt = 
⇒ Phase difference =
or 120o.
OR
From phaser
cos θ =
⇒ θ = 60o
phase difference 2θ = 120o
⇒ Phase difference =
or 120o.OR
From phaser
cos θ =
⇒ θ = 60ophase difference 2θ = 120o
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