SHMMedium
Question
Two blocks masses 3 kg and kg rest on a horizontal smooth surface . The 3 kg block is attached to a spring with a force constant k = 900 Nm-1 which is compressed 2 m from beyond the equilibrium position. The 6 kg block is ar rest at 1 m from mean position, 3 kg mass strikes the 6 kg mass the two stick together.
Options
A.velocity of the combined immediately after collision is 10 ms-1
B.velocity of the combined masses immediately after the collision is 5 ms-1
C.amplitude of the resulting oscillation is √2 m
D.amplitude of the resulting osculation is √5 / 2m.
Solution
Velocity of 3kgblock just before collision
=
=
= 300 m/s
Velocity of combined masses immediately after the collision =
= 10 m/s
Therefore v′ = ω′
⇒ 10 =
10 a′ = √2m
=
=
= 300 m/s Velocity of combined masses immediately after the collision =
= 10 m/sTherefore v′ = ω′
⇒ 10 =
10 a′ = √2mCreate a free account to view solution
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