SHMMedium
Question
Vertical displacement of a plank with a body of mass ′m′ on it is verifying according to law y = sin ωt + √3 cosωt. The minimum value of ω for which the mass just breaks off the plank and the moment it occurs first after t = 0 are by : (y is positive vertically upwards)
Options
A.
B.
C.
D.
Solution
y = sinωt + √3 cosωt = 2sin 
To berks off mg
mg = mω2min A ⇒ g = 2ω2min ⇒ ω =
Moment it occurs first after t = 0
2 = 2sin
⇒ ωt1 = 
⇒ t1 = 
To berks off mg
mg = mω2min A ⇒ g = 2ω2min ⇒ ω =
Moment it occurs first after t = 0
2 = 2sin
⇒ ωt1 = ⇒ t1 = Create a free account to view solution
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