SHMHard
Question
Displacement of a particle is x = 3 sin 2t + 4cos 2t, the amplitude and the maximum velocity will be : -
Options
A.5, 10
B.3, 2
C.4, 2
D.3, 8
Solution
x = 3sin2t + 4cos 2t = 5 sin (2t + φ)
⇒ a = 5, vmax = aω = (5)(2) = 10
⇒ a = 5, vmax = aω = (5)(2) = 10
Create a free account to view solution
View Solution FreeMore SHM Questions
If a rod of length L is hung by its end on a nail and allowed to oscillate, then find the equivalent length of simple pe...The K.E. and P.E of a particle executing SHM with amplitude A will be equal when its displacement is...The position of a particle in motion is given by y = Csinωt + Dcosωt w.r.t. origin. Then motion of the particl...A cylindrical block of mass M and area of cross section A is floating in a liquid of density $\rho$ and with its axis ve...An oscillating pendulum stops, because its energy...