SHMHard
Question
Displacement of a particle is x = 3 sin 2t + 4cos 2t, the amplitude and the maximum velocity will be : -
Options
A.5, 10
B.3, 2
C.4, 2
D.3, 8
Solution
x = 3sin2t + 4cos 2t = 5 sin (2t + φ)
⇒ a = 5, vmax = aω = (5)(2) = 10
⇒ a = 5, vmax = aω = (5)(2) = 10
Create a free account to view solution
View Solution FreeMore SHM Questions
An elastic string of length l supports a heavy particle of mass m and the system is in equilibrium with elongation produ...The angular frequency of a spring block system is ω0. This system is suspended from the ceiling of an elevator movi...In question 35 which of the graph between K.E. and time is correct ?...A cylindrical block of wood (density = 650 kg m-3), of base area 30cm2 and height 54 cm, floats in a liquid of density 9...A particle performs S.H.M with time period T. The time taken by the particle to move from half amplitude to the maximum ...