SHMMedium
Question
Displacement of a particle is x = 3 sin 2t + 4cos 2t, the amplitude and the maximum velocity will be : -
Options
A.5, 10
B.3, 2
C.4, 2
D.3, 8
Solution
x = 3sin2t + 4cos 2t = 5 sin (2t + φ)
⇒ a = 5, vmax = aω = (5)(2) = 10
⇒ a = 5, vmax = aω = (5)(2) = 10
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