A particle performs S.H.M. of amplitude A with angular frequency ω along a straight line. When

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A particle performs S.H.M. of amplitude A with angular frequency ω along a straight line. When it is at a distance A from mean positive, its kinetic energy gets increased by an amout mω²A² due to an impulsive force. What will be its new amplitude ?

Accepted Answer

at x = AKE = m&#969;2 m&#969;2A2.KE is increased by an amount of m&#969;2A2.Let nowamplitude be A1 then total Ke. KE1 = m&#969;2A2 + m&#969;2A2= m&#969;2A2 m&#969;2 &#8658; A1 = &#8730;2 A

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