Laws of MotionMedium
Question
A mass M is suspended by a rope from a rigid support at A as shown in figure. Another rope is tied at the end B, and it is pulled horizontally with a force F. If the rope AB makes an angle θ with the vertical in equilibrium, then the tension in the string AB is :
Options
A.F sin θ
B.F/sin θ
C.F cos θ
D.F cos θ
Solution
Point A is mass less so net force on it most be zero otherwise it will have ∞ acceleration.
⇒ F − Tsinθ = 0 [Equilibrium of A in horizontal direction]
⇒ T = F/sinθ
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