SHMHard
Question
Two particle A and B perform SHM along the same the same straight line the the same amplitude ′a′ same frequency ′f′ and same equilibrium position ′O′. The greatest distance between them is found to be 3a/2. At some instant of time they have same displacement from mean position. What is this displacement ?
Options
A.a / 2
B.a √7 / 4
C.√3 / a2
D.3a / 4
Solution
z1 = a sin , x2 = a sin(ωt + φ)
Greatest distance
= |x2 - x1|max = 2a sin
Now according to question x1 = x2
⇒ a sin ωt = a sin (ωt + φ)
⇒ π - ωt = ωt + φ ⇒ ωt =
⇒ x1 = a sin
= a cos 
Greatest distance
= |x2 - x1|max = 2a sin
Now according to question x1 = x2
⇒ a sin ωt = a sin (ωt + φ)
⇒ π - ωt = ωt + φ ⇒ ωt =
⇒ x1 = a sin
= a cos Create a free account to view solution
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