SHMHard
Question
The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of $176rad/s$. The frequency of this simple harmonic oscillator is___ Hz. $\left\lbrack \right.\ $ take $\left. \ \pi = \frac{22}{7} \right\rbrack$
Options
A.14
B.88
C.28
D.176
Solution
$\mathbf{\omega} = 176rad/sec$
$${f_{k} = \frac{\omega}{2\pi} = \frac{176}{2 \times 22} \times 7 }{= \frac{176}{44} \times 7 }{= 4 \times 7 = 28\text{ }Hz }$$So frequency of oscillator
$$= \frac{f_{k}}{2} = 14\text{ }Hz$$
Create a free account to view solution
View Solution FreeMore SHM Questions
A particle is subjected to two mutually perpendicular simple harmonic motions such that its x and y coordinates are give...A simple pendulum has a time period T1 when on the earth′s surface and T2 when taken to a height R above the earth...An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass M. The piston and the ...Equation of SHM is x = 10 sin 10πt. Find the distance between the two points where speed is 50π cm/sec. x is i...The time period of small oscillations of mass m : -...