SHMMedium
Question
The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of $176rad/s$. The frequency of this simple harmonic oscillator is___ Hz. $\left\lbrack \right.\ $ take $\left. \ \pi = \frac{22}{7} \right\rbrack$
Options
A.14
B.88
C.28
D.176
Solution
$\mathbf{\omega} = 176rad/sec$
$${f_{k} = \frac{\omega}{2\pi} = \frac{176}{2 \times 22} \times 7 }{= \frac{176}{44} \times 7 }{= 4 \times 7 = 28\text{ }Hz }$$So frequency of oscillator
$$= \frac{f_{k}}{2} = 14\text{ }Hz$$
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