Gaseous StateHard

Question

Two glass bulbs  A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100 cm3 and contained the gas, while bulb B was empty. On opening the stop cock, the pressure fell down to 40% . The volume of the bulb B must be :

Options

A.75 cm3
B.125 cm3
C.150 cm3
D.250 cm3

Solution


   VA = 100           VB = V ml
          ml
PA VA = PA′ V′       Where  V′ = VA + VB = (VA + V) ml
PA 100 = PA × V′    PA = PA
250 = V′     ⇒  VA + V = 250 ml
                                  V = 150 ml

Create a free account to view solution

View Solution Free
Topic: Gaseous State·Practice all Gaseous State questions

More Gaseous State Questions

1120.0 mL of ozonized oxygen at S.T.P. weighs 1.76 g. Calculate the volume of oxygen in the ozonized oxygen....Consider the following statements: The coefficient B in the virial equation of state(i) is independent of temperature(ii...Helium atom is two times heavier than a hydrogen molecule. At 298 K, the average kinetic energy of a helium atom is :...The root mean square velocity of an ideal gas to constan pressure varies with density (d) as :...A real gas obeying Vander Waal′s equation will resemble ideal gas, if the :...