Gaseous StateHard

Question

Two glass bulbs  A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100 cm3 and contained the gas, while bulb B was empty. On opening the stop cock, the pressure fell down to 40% . The volume of the bulb B must be :

Options

A.75 cm3
B.125 cm3
C.150 cm3
D.250 cm3

Solution


   VA = 100           VB = V ml
          ml
PA VA = PA′ V′       Where  V′ = VA + VB = (VA + V) ml
PA 100 = PA × V′    PA = PA
250 = V′     ⇒  VA + V = 250 ml
                                  V = 150 ml

Create a free account to view solution

View Solution Free
Topic: Gaseous State·Practice all Gaseous State questions

More Gaseous State Questions

The volume of CO2 produced by the combustion of 40 ml of gaseous acetone in excess of oxygen is...Identify the correct statements when a fixed amount ideal gas is heated in from 300 to 600 K in a container fitted with ...Henry′s law constants for four gases are given below at 293 K. Which one is more soluble in water at that temperat...A real gas obeying Vander Waal′s equation will resemble ideal gas, if the :...Equal masses of methane and oxygen are mixed in an empty container at 25oC. The fraction of the total pressure exerted b...