Chemical Kinetics and Nuclear ChemistryHard
Question
A reaction takes place in three steps having rate constants K1, K2, K3 respectively. The overall rate constant K = 
. If energies of activations for the three steps are 40, 30, 20 kJ respectively, the overal energy of activation is :
. If energies of activations for the three steps are 40, 30, 20 kJ respectively, the overal energy of activation is :Options
A.10
B.15
C.30
D.60
Solution
given K = 
we know that for any reaction
so differentiating the given relation of k with k1, k2 & k3 with respect to temperature, we have
= 
Ea = Ea3 + Ea1 - Ea2
= (20 + 40 - 30) = 30 kJ/mol
we know that for any reaction
so differentiating the given relation of k with k1, k2 & k3 with respect to temperature, we have
= Ea = Ea3 + Ea1 - Ea2
= (20 + 40 - 30) = 30 kJ/mol
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
The half-life of a first-order reaction is 10 minutes. In what time, the rate of reaction will decrease from 6.0 × 1021 ...Acid catalysed hydrolysis of ester is first-order reaction and rate constant is given by k = where V0, Vt and V∞ a...The specific constant of a first order reaction depends on the :...Two reaction, A → products and B → products have rate constants Ka and Kb at temperature T and activation en...For a third order reactions : 3X → Y + Z the initial rate is 5 × 10-2 mol L-1S-1 when the conc. of X is 0.1 m...