Chemical Kinetics and Nuclear ChemistryHard

Question

Graph between log k and 1/T (k is rate constant in s-1 and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line = - then Ea is :

Options

A.2.303 × 2 cal
B.cal
C.2 cal
D.None of these

Solution

We know,        log K = log A -
compare this by        y = mx + c
m = - slope of this
Given  
Ea = R = 2 cal

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