Chemical Kinetics and Nuclear ChemistryHard

Question

Graph between log k and 1/T (k is rate constant in s-1 and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line = - then Ea is :

Options

A.2.303 × 2 cal
B.cal
C.2 cal
D.None of these

Solution

We know,        log K = log A -
compare this by        y = mx + c
m = - slope of this
Given  
Ea = R = 2 cal

Create a free account to view solution

View Solution Free
Topic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions

More Chemical Kinetics and Nuclear Chemistry Questions

In gaseous reactions important for the understanding of the upper atmosphere, H2O and O react bimolecularly to form two ...A catalyst lowers the activation energy of a reaction from 20 kJ mol-1 to 10 kJ mol-1. The temperature at which the unca...For a certain reaction of order ‘n’, the time for half change t1/2 is given by $t_{1/2} = \frac{\left\lbrack 2 - \sqrt{2...Which of the following statement is incorrect?...The colligative property is not represented by :...