Chemical Kinetics and Nuclear ChemistryHard
Question
Graph between log k and 1/T (k is rate constant in s-1 and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line = - 
then Ea is :
then Ea is :Options
A.2.303 × 2 cal
B.
cal
calC.2 cal
D.None of these
Solution
We know, log K = log A - 
compare this by y = mx + c
m = -
slope of this
Given
Ea = R = 2 cal
compare this by y = mx + c
m = -
slope of thisGiven
Ea = R = 2 cal
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