Chemical Kinetics and Nuclear ChemistryHard
Question
A reaction of first-order completed 90% in 90 minutes, hence, it is completed 50% in approximately :
Options
A.50 min
B.54 min
C.27 min
D.62 min
Solution
K = 
log 
× log10 = 
min-1
t1/2 (50% completed) =
× 90 = 27.08 minutes.
log × log10 = min-1t1/2 (50% completed) =
× 90 = 27.08 minutes. Create a free account to view solution
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