NEETElectrochemistryHard
Question
For the cell (at 298 K) Ag(s) | AgCl(s) | Cl- (aq) || AgNO3 (aq) | Ag(s)
Which of following is correct -
Which of following is correct -
Options
A.The cell emf will be zero when [Ag+]a = [Ag+]c ([Ag+] in anodic compartment = [Ag+] in cathodic compartment)
B.The amount of AgCl(s) precipitate in anodic compartment will decrease with the working of the cell.
C.The concentration of [Ag+] = constant, in anodic compartment during working of cell.
D.Ecell = EoAg+/Ag - EoCl-|AgCl|Ag - 
Solution
ECell = EoCell -
; At [Ag+]c = [Ag+]a equilibrium will achieve and K = Ksp = [Ag+]a[Cl-]a
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Limiting molar conductivity of NH4OH (i.e. Λm (NH4OH)) is equal to :...MnO4- + 8H+ + 5e- → Mn2+ + 4H2O ; Eo = 1.51 V ; ᐃGo1 = - 5 × 1.51 × FMnO2 + 4H+ + 2e- → Mn2+...For the process: Cu2+ + 2e− → Cu; log[Cu2+] vs. Ered graph is shown in the figure, where OA = 0.34 V. The electrode pote...IV CH2 = NHAmong these compounds, the correct order of C - N bond lengths is :...Calculate the cell EMF in mV for Pt | H2 (1atm) | HCl (0.01 M) | AgCl(s) | Ag(s) at 298 Kif ᐃGfo values are at 25o...