ElectrochemistryHard
Question
The conductivity of a solution of AgCl at 298 K is found to be 1.382 × 10-6 W-1 cm-1. The ionic conductance of Ag+ and Cl- at infinite dilution are 61.9 W-1 cm2 mol-1 and 76.3 W-1 cm2 mol-1, respecitvley. The solubility of AgCl is
Options
A.1.4 × 10-5 mol L-1
B.1 × 10-2 mol L-1
C.1 × 10-5 mol L-1
D.1.9 × 10-5 mol L-1
Solution
K = 1.382 × 10-6 s cm-1
ΛAgCl = 61.9 + 76.3 = 138.2 =
S = 10-5 M.
ΛAgCl = 61.9 + 76.3 = 138.2 =
S = 10-5 M.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
If same quantity of electricity is passed through three electrolytic cells containing FeSO4, Fe2(SO4)3 and Fe(NO3)3, the...EMF of the cell: Cd(s)|CdCl2.5H2O (sat.)|AgCl(s)|Ag(s) is +0.70 V at 0°C and +0.60 V at 50°C. If ΔHo and ΔSo are tempera...The EMF for the cell: Ag(s)|AgCl(s)|KCl(0.2 M)||KBr (0.001 M)|AgBr(s)|Ag(s) at 25°C is (Ksp(AgCl) = 2.0 × 10−10; Ksp(AgB...The standard reduction potentials at 25°C of Li+|Li, Ba2+|Ba, Na+|Na and Mg2+|Mg are −3.05, −2.73, −2.71 and −2.37 V, re...Molar conductance of BaCl2, H2SO4 and HCl at infinite dilutions are x1, x2 and x3 respectively.Equivalent conductance of...