ElectrochemistryHard
Question
The conductivity of a solution of AgCl at 298 K is found to be 1.382 × 10-6 W-1 cm-1. The ionic conductance of Ag+ and Cl- at infinite dilution are 61.9 W-1 cm2 mol-1 and 76.3 W-1 cm2 mol-1, respecitvley. The solubility of AgCl is
Options
A.1.4 × 10-5 mol L-1
B.1 × 10-2 mol L-1
C.1 × 10-5 mol L-1
D.1.9 × 10-5 mol L-1
Solution
K = 1.382 × 10-6 s cm-1
ΛAgCl = 61.9 + 76.3 = 138.2 =
S = 10-5 M.
ΛAgCl = 61.9 + 76.3 = 138.2 =
S = 10-5 M.
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