ElectrochemistryHard

Question

Molar conductance of 0.1 M acetic acid is 7 ohm-1 cm2 mol-1. If the molar cond. of acetic acid at infinite dilution is 380.8 ohm-1 cm2 mol-1, the value of dissociation constant will be :

Options

A.226 × 10-5 mol dm-3   
B.1.66 × 10-3 mol dm-1
C.1.66 × 10-2 mol dm-3
D.3.442 × 10-5 mol dm-3

Solution

Ka = Cα2 = 0.1 × = 3.38 × 10-5

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