Laws of MotionMedium
Question
If the acceleration of the elevator a0 > g, then
If the acceleration of the elevator a0 > g, then
If the acceleration of the elevator a0 > g, then
Options
A.the acceleration of the masses will be a0
B.the acceleration of the masses will be (a0 - g)
C.the tension in the string will be 
(g - a0)
(g - a0)D.tension in the string will be zero
Solution
Let acceleration of massesw.r.t pulley be a
Mg - T - Ma0 = ma
T + ma0 - mg = ma
⇒ (M - m)g - (M = m)a0 = (m + M)a
⇒ a =
(g - a0)
But a0 > g so a < 0 and T < 0
⇒ Tension in string will be zero
Mg - T - Ma0 = ma
T + ma0 - mg = ma
⇒ (M - m)g - (M = m)a0 = (m + M)a
⇒ a =
(g - a0)But a0 > g so a < 0 and T < 0
⇒ Tension in string will be zero
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