Laws of MotionHard
Question
A light string at one end to a clamp on group over a fixed pulley and hangs at the other side. It makes on angle of 30o with the ground . A monkey of mass 5 kg climbs up the rope. The clamp can tolerate a vertical force of 40 N only . The maximum acceleration in upward direction with which the with which the monkey can clump safely is (neglect friction and take g = 10 m/s2)
Options
A.2 m/s2
B.4 m/s2
C.6 m/s2
D.8 m/s2
Solution
Maximum tension in string Tmax sin 30o = 40
⇒ Tmax =
= 80 N
For Monkey Tmax - mg = mg ⇒ a =
- 10 = 6 ms-2
⇒ Tmax =
= 80 NFor Monkey Tmax - mg = mg ⇒ a =
- 10 = 6 ms-2Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
The mass of a lift is 500 Kg. If the lift is moving downwards with an acceleration of 2m / sec2, the tension on the stri...The rear side of a truck is open and a box of mass 20 kg is placed on the truck 4m away from the open end, μ = 0.15...System is shown in figure and wedge is moving towards left with speed 2 m/s. Then velocity of the block B will be:...In the figure shown all the surface are smooth. All the blocks A, B and C are movable X-axis is horizontal and y-axis ve...Objects A and B each of mass m are connected by light inextensible cord. They are constrained to move on a frictionless ...