Laws of MotionHard
Question
A light string at one end to a clamp on group over a fixed pulley and hangs at the other side. It makes on angle of 30o with the ground . A monkey of mass 5 kg climbs up the rope. The clamp can tolerate a vertical force of 40 N only . The maximum acceleration in upward direction with which the with which the monkey can clump safely is (neglect friction and take g = 10 m/s2)
Options
A.2 m/s2
B.4 m/s2
C.6 m/s2
D.8 m/s2
Solution
Maximum tension in string Tmax sin 30o = 40
⇒ Tmax =
= 80 N
For Monkey Tmax - mg = mg ⇒ a =
- 10 = 6 ms-2
⇒ Tmax =
= 80 NFor Monkey Tmax - mg = mg ⇒ a =
- 10 = 6 ms-2Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
In the figure. the position- time graph of a particle of mass 0.1 kg is show. The impulse at t = 2 second is...A balloon of mass M is descending at a constant acceleration α. When a mass m is released from the balloon it start...A force-time graph for the motion of a body is shown in fig. Change in linear momentum between 0 and 8 s is :-...A block of mass 200 kg is being pulled up by men on an inclined plane at angle of 45o as shown. The coefficient of stati...A test tube is filled with water and end closed. It contains a small steel ball and an air bubble. The test tube is rota...