Laws of MotionHard
Question
In the figure. the position- time graph of a particle of mass 0.1 kg is show. The impulse at t = 2 second is
Options
A.0.2 kgms-1
B.- 0.2 kgms-1
C.0.1 kgms-1
D.-0.4 kgms-1
Solution
Impulse = Change in momentum
= m(v2 - v1) = 0.1
= - 0.2 kg ms-1
= m(v2 - v1) = 0.1
= - 0.2 kg ms-1Create a free account to view solution
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