Laws of MotionMedium
Question
A car is going at speed of 6m/s when it encounters a 15 m slope of angle 300. The friction coefficient between the road and tyre is 0.5. The driver applies the brakes. The minimum speed of car with which it can reach the bottom is(g =10 m/s2)
Options
A.4 m/s
B.3 m/s
C.7.49 m/s
D.8.45 m/s
Solution
Acceleration of car along slope
= g sin θ = μ g cos θ
= 10 ×
- (0.5)(10)
= 5 - 4.33
= 0.67 ms-2
Now from v2 = u2 + 2as
v =
=
= 7.49 ms-1
= g sin θ = μ g cos θ
= 10 ×
- (0.5)(10) = 5 - 4.33= 0.67 ms-2
Now from v2 = u2 + 2as
v =
=
= 7.49 ms-1
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