Laws of MotionMedium

Question

In the system shown in the figure  m1 > m2 . System is held at rest by thread BC . Just after the thread BC is burnt :

Options

A.acceleration of m2  will be upwards
B.magnitude of acceleration of both blocks will be equal to
C.acceleration of m1 will be equal to zero
D.magnitude of acceleration of two blocks will be non-zero and unequal.

Solution


T = m1g
when thred is burnt, tension in spring remains same = m1g.
m1g − m2g = m2a    g =     a = upwards 

for m1      a = 0

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