Laws of MotionMedium
Question
In then arrangement show in the figure, mass of the block B and A is 2m and m respectively. Surface between B and floor is smooth. The block B is connected to the block c by means of a string pukka system. If the whole system is released. Then find the minimum value of mass of block C so that A remains stationary w.r.t B. Coefficient of friction between S and B isμ
Options
A.
B.
C.
D.
Solution
let the mass of ′C′ be M of ′A′ remains stationary
Acceleration of system a =
A is stationary w.r.t. to ′B′
GBD of A
μN = mg
⇒ Mμ - M = 3M ⇒ M =
Acceleration of system a =
A is stationary w.r.t. to ′B′
GBD of A
μN = mg
⇒ Mμ - M = 3M ⇒ M =
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