Laws of MotionMedium
Question
In the arrangement show in figure m1=1kg, m2=2kg. pulleys are mass less and strings are light. For What value of M the mass m1moves with constant velocity (Neglect friction)
Options
A.6 kg
B.4 kg
C.8 kg
D.10 kg
Solution
T = M ×
.........(i)
20 -
2 × a
20 -
= 2a
&
= 1 × g ⇒ T = 20 N
20 - 10 = 2a ⇒ a = 5 m/s2
20 -
= 2 × 5 ⇒ m = 
M = 8 kg
.........(i)20 -
2 × a20 -
= 2a&
= 1 × g ⇒ T = 20 N20 - 10 = 2a ⇒ a = 5 m/s2
20 -
= 2 × 5 ⇒ m = M = 8 kg
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