Laws of MotionMedium
Question
In the arrangement show in figure, pulley is smooth and mass less and all the strings are light. let F1 be the force exerted on the pulley in case (i) and F2 the force in case (ii). then
Options
A.F1 > F2
B.F1 < F2
C.F1 = F2
D.F1 = 2F2
Solution
Case (ii) : F1 = 2T1
a1 =
∴ T1 = 2mg = 2m ×
⇒ T1 =
Case (ii) : F2 = 2T2
a2 =
∴ 4mg - T2 = ×
T2 =
∴ F2 = 2T2 = 
a1 =
∴ T1 = 2mg = 2m ×
⇒ T1 =
Case (ii) : F2 = 2T2
a2 =
∴ 4mg - T2 = ×
T2 =
∴ F2 = 2T2 = Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A astronaut accidentally gets separated out of his small spaceship accelerating in inter-stellar space at a constant acc...A block B of mass 0.6 kg slides down the smooth face PR of a wedge A of mass 1.7 kg which can move freely on a smooth ho...Newton′s first law of motion describes the following...There force F1,F2and F3 act on an object simultaneously. There force vectors are shown are shown in the following free-b...A block of mass 0.1 kg. is pressed against a wall with a horizontal force of 5N as shown in the figure. If the coefficie...