Laws of MotionHard
Question
In the arrangement show in figure, pulley is smooth and mass less and all the strings are light. let F1 be the force exerted on the pulley in case (i) and F2 the force in case (ii). then
Options
A.F1 > F2
B.F1 < F2
C.F1 = F2
D.F1 = 2F2
Solution
Case (ii) : F1 = 2T1
a1 =
∴ T1 = 2mg = 2m ×
⇒ T1 =
Case (ii) : F2 = 2T2
a2 =
∴ 4mg - T2 = ×
T2 =
∴ F2 = 2T2 = 
a1 =
∴ T1 = 2mg = 2m ×
⇒ T1 =
Case (ii) : F2 = 2T2
a2 =
∴ 4mg - T2 = ×
T2 =
∴ F2 = 2T2 = Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A frame will be inertial if it moves with respect to another inertial frame with a constant :-...A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in time t1 when e...System is shown in the figure. Velocity of sphere A is 9 m/s. Then speed of sphere B will be:...A block tied between two springs is in equilibrium. If upper spring is cut then the acceleration of the block just after...A body is moving with a speed of 1 m/s and a force F is needed to stop it in a distance x. If the speed of the body is 3...