Laws of MotionHard
Question
The ratio of the weight of a man in a stationary lift & when it is moving downward with uniform acceleration ′a′ is 3 : 2 . The value of ′a′ is : (g = acceleration. due to gravity)
Options
A.(3/2) g
B.g
C.(2/3) g
D.g/3
Solution
mg − n = ma [Newton′s II law for man]
⇒ N = m (g − a)
Weight of man in moving lift is equal to N.
⇒
⇒ a = g/3Create a free account to view solution
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