Laws of MotionMedium
Question
A trolley is accelerating down an incline of angle θ with acceleration g sin θ. Which of the following is correct. (a is the constant angle made by the string with vertical).
Options
A.α = θ
B.α = 0o
C.Tension in the string, T = mg
D.Tension in the string, T = mg sec θ
Solution
F.B.D. of mass m is w.r.t. trolley
T sin (α − θ) + mg sin θ − FP = 0 [Equilibrium of mass in x direction w.r.t. trolley]
⇒ T sin (α − θ) + mg sin θ − mg sin θ = 0
⇒ T sin (α − θ) = 0
since T cant be zero , sin (α − θ) must be zero
⇒ α = θ
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