Laws of MotionHard
Question
A trolley is accelerating down an incline of angle θ with acceleration g sin θ. Which of the following is correct. (a is the constant angle made by the string with vertical).


Options
A.α = θ
B.α = 0o
C.Tension in the string, T = mg
D.Tension in the string, T = mg sec θ
Solution

F.B.D. of mass m is w.r.t. trolley
T sin (α − θ) + mg sin θ − FP = 0 [Equilibrium of mass in x direction w.r.t. trolley]
⇒ T sin (α − θ) + mg sin θ − mg sin θ = 0
⇒ T sin (α − θ) = 0
since T cant be zero , sin (α − θ) must be zero
⇒ α = θ
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
A block slips with constant velocity on a plane inclined at an angle θ. The same block is pushed up the plane with ...A block of mass 15 kg is placed on a long trolley. The cofficient of friction between the block and trolley is 0.18. The...System is shown in the figure. Assume that cylinder remains in contact with the two wedges. The velocity of cylinder is ...A block B of mass 0.6 kg slides down the smooth face PR of a wedge A of mass 1.7 kg which can move freely on a smooth ho...A trolley of the mass 5kg on a horizontal smooth surface is pulled by a load of mass 2kg by means of uniform rope BC of ...