SolutionHard
Question
Mole fraction of the toluene in the vapour phase which is in equilibrium with a solution of benzene (po = 120 Torr) and toluene (po = 80 Torr) having 2.0 mol of each is
Options
A.0.50
B.0.25
C.0.60
D.0.40
Solution
PT = XA poA + XB poB
=
× 80 + 
× 120 = 100 Torr
Now mole fraction in vapour phase =
= 0.4.
=
× 80 + × 120 = 100 TorrNow mole fraction in vapour phase =
= 0.4.Create a free account to view solution
View Solution FreeMore Solution Questions
Solubility curves of four ionic salts X, Y, Z, W are given below :In which case the value of ᐃHsol. < 0...In mixture A and B component show - ve deviation as...Which facts are true when we use van′t Hoff equation PV = CST for osmotic pressure P of dilute solutions ?...At 35°C, the vapour pressure of CS2 is 512 mm Hg and that of acetone CH3COCH3 is 344 mm Hg. A solution of CS2 and aceton...For 1 molal aqueous solution of the following compounds, which one will show the highest freezing point ?...