SolutionHard
Question
Mole fraction of the toluene in the vapour phase which is in equilibrium with a solution of benzene (po = 120 Torr) and toluene (po = 80 Torr) having 2.0 mol of each is
Options
A.0.50
B.0.25
C.0.60
D.0.40
Solution
PT = XA poA + XB poB
=
× 80 + 
× 120 = 100 Torr
Now mole fraction in vapour phase =
= 0.4.
=
× 80 + × 120 = 100 TorrNow mole fraction in vapour phase =
= 0.4.Create a free account to view solution
View Solution FreeMore Solution Questions
Equimolar solutions in the same solvent have...For a solution of 0.849 g of mercurous chloride in 50 g of HgCl2(l) the freezing point depression is 1.24oC. Kf for HgCl...Pressure over an ideal binary liquid solution containing 10 moles each of liquid A and B is gradually decreased isotherm...Select correct statement :...The vapour pressure of pure benzene, C6H6 at 50oC is 268 Torr. How many moles of non-volatile solute per mol of benzene ...