SolutionHard
Question
An aqueous solution of a solute AB has b.p. of 101.08oC (AB is 100% ionised at boiling point of the solution) and freezes at - 1.80oC. Hence, AB (Kb / Kf = 0.3)
Options
A.is 100% ionised at the f.p. of the solution
B.behaves as non-electrolyte at the f.p. of the solution
C.forms dimer
D.none of the above
Solution
Given ᐃTb = 1.08oC, i = 2 at boiling pt. of solution.
and ᐃTf = 1.80oC, and
= 0.3]
So
so if = 1
i.e., AB behaves as non–electrolyte at the f.p of the solution.
and ᐃTf = 1.80oC, and
= 0.3]So
so if = 1
i.e., AB behaves as non–electrolyte at the f.p of the solution.
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