Laws of MotionHard
Question
With What acceleration ′a′ show the elevator descends so that the block of mass M exerts a force of 
on the wigging machine ? [g= acceleration due to gravity]
on the wigging machine ? [g= acceleration due to gravity]Options
A.0.3g
B.0.1g
C.0.9g
D.0.6g
Solution
FBD of block : 
Mg-N=Ma; Now according to question N = 
So a = 
= 0.9g
Mg-N=Ma; Now according to question N = So a = = 0.9gCreate a free account to view solution
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