Laws of MotionHard
Question
With What acceleration ′a′ show the elevator descends so that the block of mass M exerts a force of 
on the wigging machine ? [g= acceleration due to gravity]
on the wigging machine ? [g= acceleration due to gravity]Options
A.0.3g
B.0.1g
C.0.9g
D.0.6g
Solution
FBD of block : 
Mg-N=Ma; Now according to question N = 
So a = 
= 0.9g
Mg-N=Ma; Now according to question N = So a = = 0.9gCreate a free account to view solution
View Solution FreeMore Laws of Motion Questions
A man of mass 50 kg is pulling on a plank of mass 100 kg kept on a smooth floor as shown with force of 100 N. If both ma...In the given figure, what is the reading of the spring balance ?...There are three Newton′s laws of motion namely I, II and III ; we can derive : -...Two masses of 1 kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. Th...A man of weight 75 kg is standing in an elevator moving with an acceleration of 5 m/s2 in upward direction. The apparent...