Atomic StructureHard
Question
If there are only two H-atoms, each is in 3rd excited state then :
Options
A.Maximum number of different photons emitted is 4.
B.Maximum number of different photos emitted is 3.
C.Minimum number of different photons emitted is 1.
D.Minimum number of different photons emitted is 2.
Solution
Max. number of different photons emitted is 4 [(4 → 3 → 1 and 4 → 2 → 1) or (4 → 3 → 2 → 1 and 4 → 1)].
Minimum number of different photons emitted is 1(4 → 1 and 4 → 1).
Minimum number of different photons emitted is 1(4 → 1 and 4 → 1).
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