Atomic StructureHard
Question
If there are only two H-atoms, each is in 3rd excited state then :
Options
A.Maximum number of different photons emitted is 4.
B.Maximum number of different photos emitted is 3.
C.Minimum number of different photons emitted is 1.
D.Minimum number of different photons emitted is 2.
Solution
Max. number of different photons emitted is 4 [(4 → 3 → 1 and 4 → 2 → 1) or (4 → 3 → 2 → 1 and 4 → 1)].
Minimum number of different photons emitted is 1(4 → 1 and 4 → 1).
Minimum number of different photons emitted is 1(4 → 1 and 4 → 1).
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Photon having energy equivalent to the binding energy of 4th state of He+ ion is used to eject an electron from the meta...The number of possible lines of Paschen series when electron jumps from 7th excited state to ground state (in hydrogen l...A photon of 300 nm is absorbed by a gas and then emits two photons. One photon has a wavelength 496 nm then the waveleng...The ratio of potential energy of electron in the third orbit of Li2+ ion to the kinetic energy of electron in the fourth...The number of d-electrons in Fe2+ (Z = 26) is not equal to the number of electrons in which one of the following?...