Current Electricity and Electrical InstrumentHard

Question

A circuit is comprised of eight identical batteries an a resistor R = 0.8W. Each battery has an emf of 1.0 V and internal resistance of 0.2W. The voltage difference across any of the battery is

Options

A.0.5 V
B.1.0 V
C.0V
D.2V

Solution

⇒
1.6 I1 - 0.8 I2 = 4          ........(i)
1.6 I2 - 0.8 I1 = 4          ........(ii)
from eq. I1 = I2 = 5
voltage difference across any of the battery.

Va - 1 + 0.2 × 5 - Vb = 0
Va - Vb = 0 Volt

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