Atomic StructureHard

Question

A bulb of 40 W is producing a light of wavelength 620 nm with 80% of efficiency then the number of photons emitted by the bulb in 20 seconds are (1eV = 1.6 × 10-19 J, hc = 12400 eV (Ao))

Options

A. 2 × 1018
B.1018
C.1021
D.2 × 1021

Solution

Power = ⇒ 40 ×    ⇒  n = 2 × 1021

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