Straight LineHard
Question
For a > b > c > 0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and bx + ay + c = 0 is less than 2√2 Then
Options
A.a + b - c > 0
B.a - b + c < 0
C.a - b + c > 0
D.a + b - c < 0
Solution
Point of intersection of both lines is
Distance between
Distance =
a + b + c < 2(a + b)
a + b - c > 0
According to given condition option (C) also correct.
Distance between
Distance =
a + b + c < 2(a + b)
a + b - c > 0
According to given condition option (C) also correct.
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