ElectrostaticsHard
Question
An infinite, uniformly charged sheet with surface charge density cuts through a spherical Gaussian surface of radius R at a distance x from its center, as shown in the figure. The electric flux φ through the Gaussian surface is :
Options
A.
B.
C.
D.
Solution
∴ Electric field = 
due to infinitely uniform charged.
Electric flux
× [πR2 - πx2]
due to infinitely uniform charged.Electric flux
× [πR2 - πx2]Create a free account to view solution
View Solution FreeMore Electrostatics Questions
For a dipole, the value of each charge is 10−10 state coulomb and separation is 1, then its dipole moment is : -...A point charges 50μC is located in the XY plane at the point of position = (2î + 3ĵ) vector meter. What i...A charge + q is fixed at each of the points x = x0, x = 3x0, x = 5x0 ...... ∞ on the x-axis and charge - q is fixe...A solid sphere of radius R has a volume charge density ρ = ρ0 r2 ( Where ρ0 is a constant and ρ0 is ...An electric dipole is made up of two equal and opposite charges of 2μc at a distance of 3 cm. This is kept in an el...