ElectrostaticsHard
Question
The capacitors C1,C3 ,C4 ,C5 have a capacitance 4μF each and C2 has capacitance 10μF. The effective capacitance between Pand Q will be :


Options
A.8 μF
B.6 μF
C.4 μF
D.2 μF
Solution

The combination forms Wheatstone bridge as

So, central capactor, that is C2 becomes ineffective. Now eqivalent circut will become as follows.
Now, two C are in series, their equivalent capacity
and them two
are in parallel so their equivalent capacity will be 
So, toral capacity = C = 4μF
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