ElectrostaticsHard

Question

The capacitors C1,C3 ,C4 ,C5 have a capacitance 4μF each and C2 has capacitance 10μF. The effective capacitance between Pand Q will be :
     

Options

A.8 μF
B.6 μF
C.4 μF
D.2 μF

Solution

       
The combination forms Wheatstone bridge as
So, central capactor, that is C2 becomes ineffective. Now eqivalent circut will become as follows.
Now, two C are in series, their equivalent capacity
and them two are in parallel so their equivalent capacity will be

So, toral capacity = C = 4μF

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