Gauss LawMedium
Question
Charges Q1 and Q2 lies inside and outside respectively of a closed surface S. Let E be the field at any point on S and be the flux of E over S.
Options
A.If Q1 changes, both E and φ will change.
B.If Q2 changes, E will change but φ will not change.
C.If Q1 = 0 and Q2 ≠ 0 then E ≠ 0 but φ = 0
D.If Q1 ≠ 0 and Q2 = 0 then E = 0 but φ = 0
Solution
Electric flux depends on the total charge enclosed by the closed surface S. Hence flux is related with charge Q1. Electric field at a point is the vector sum of the all electric field intensities due to all charges.
Create a free account to view solution
View Solution FreeMore Gauss Law Questions
Two infinitely long parallel conducting plates having surface charge density +σ and -σ respectively, are sep...Let E1(r), E2(r) and E3(r) be the respective electric fields at a distance r from a point charge Q, an infinitely long w...Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a dista...A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 volts. The electric field a...If the electric flux entering and leaving a closed surface are respectively of magnitude φ1. and φ2, then the ...