ElectrostaticsHard
Question
A horizontal electric field (E = (mg)/q) exists as shown in figure and a mass m attached at the end of a light rod. If mass m is released from the position shown in figure find the angular velocity of the rod when it passes through the bottom most position :
Options
A.
B.
C.
D.
Solution
By work energy theorem Wg + Welec = ᐃKE
mgl
+ qE × 
mv2 - 0
mgl
+ qE × mv2 - 0Create a free account to view solution
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