Momentum and CollisionHard
Question
The fig. shows a of equally placed beads of mass m, separated by distance d. The beads are free to slide without friction on a thin wire. A constant force F acts no the frost bead initially at rest till it makes collision with the second bead. The second bead then collides with the third so on Suppose that all collisions are elastic


Options
A.Speed of the first bead immediately before and immediately after its collision with the second bead is
and zero respectively
B.Speed of the first bead immediately before and immediately after collision with the seconded is
and
respectively
C.Speed of the first bead immediately after its collision with third bead is zero
D.The average speed of the first bead is
Solution
In elastic head on collision if the masses of the colliding bodies are equal, the velocities after collision are interchanged.
For Ist bead , Fd =
mu2 ⇒ u =
For Ist bead , Fd =
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A particle of mass m moving in XY horizontal plane strikes the end of the vertical rod at an angle 37o with Y-axis. Rod ...A spherical ball is dropped in a long column of viscous liquid. Which of the following graphs represent the variation of...A wooden block of volume 1000 cm3 is suspended from a spring balance. Its weight is 12 N in air. It is suspended in wate...Three man A, B and C mass 40 kg, 50 kg 60 are standing on a plank pf mass 90 kg, which is. kept on a smooth horizontal p...An increases in pressure required to decreases the 200 liters volume of a liquid by 0.004% in container is : (Bulk modul...