Momentum and CollisionHard
Question
The fig. shows a of equally placed beads of mass m, separated by distance d. The beads are free to slide without friction on a thin wire. A constant force F acts no the frost bead initially at rest till it makes collision with the second bead. The second bead then collides with the third so on Suppose that all collisions are elastic
Options
A.Speed of the first bead immediately before and immediately after its collision with the second bead is
and zero respectively
and zero respectively B.Speed of the first bead immediately before and immediately after collision with the seconded is and 
respectively
and respectively C.Speed of the first bead immediately after its collision with third bead is zero
D.The average speed of the first bead is
Solution
In elastic head on collision if the masses of the colliding bodies are equal, the velocities after collision are interchanged.
For Ist bead , Fd =
mu2 ⇒ u = 
For Ist bead , Fd =
mu2 ⇒ u = Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A large number (n) of identical beads, each of mass m and radius r are strung on a thin smooth rigid horizontal rod of l...A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throiws a stone of 0.5 k...The figure shows the position - time (x - t) graph of one-dimensional motion of a body of mass 0.4 kg. The magnitude of ...In which of the following cases, the centre of the mass of a rod may be at its centre ?...A brass rod of cross-sectional area 1 cm2 and length 0.2 m is compressed lengthwise by a weight of 5 kg. If Young′...