Momentum and CollisionHard
Question
A bomb of mass 9 kg explodes into two pieces of masses 3 kg and 6 kg. The velocity of mass 3 kg is 16 m/s. The KE of mass 6 kg in joule is :-
Options
A.96
B.384
C.192
D.192
Solution
According to law of conservation of momentum 0 = m1v1+ m2v2
K2 =
m2v22 = 
= 192 J
K2 =
m2v22 = = 192 JCreate a free account to view solution
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