Momentum and CollisionHard
Question
A small bucket of mass M kg is attached to a long inextensible cord of length L m. The bucket is released from rest when the cord is in a horizontal position. An its lowest position, the bucket scoops up m kg of water and swings up to a height h. height h in meters 9s
Options
A.
L
LB.
L
LC.
L
LD.
L
LSolution
At the lowest position
COME : M
= (M + m) v.....(i)
COME :
(M + m)v2 = (M + m) gh....(ii)
⇒ v =
= 
⇒ h = 
L.
COME : M
= (M + m) v.....(i)COME :
(M + m)v2 = (M + m) gh....(ii)⇒ v =
= ⇒ h = L.Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
Consider an one dimensional elastic between a given incoming body A and B, initially at rest. The mas of B in comparison...In a capillary tube experiment, a vertical 30 cm long capillary tube is dipped in water. The water rises up to a height ...Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average t...An Arrow sign is made by cutting and rejoining a quarter part of a plate of side ′L′ as shown. The distance ...The moment of inertia of a rod about an axis through its centre and perpendicular to it is ML2 (where M is the mass and ...