Solid StateHard

Question

If the anions (A) form hexagonal closest packing and cations (C) occupy only 2/3 octahedral voids in it, then the general formula of the compound is :

Options

A.CA
B.CA2
C.C2A3
D.C3A2

Solution

for A, hcp packing         so   effective no = 6
for C,  6 × 2/3 = 4
A6C4    or     A3C2

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