SolutionMedium
Question
On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be (molar mass of heptane= 100 g mol-1 and of octane = 114 g mol-1).
Options
A.72.0 kPa
B.36.1 kPa
C.96.2 kPa
D.144.5 kPa
Solution
Mole fraction of Heptane = 
XHeptane = 0.45
∴ Mole fraction of octane = 0.55 = Xoctane
Total pressure =
= (105 × 0.45) + (45 × 0.55) kPa
= 72.0 KPa
Mole fraction of Heptane =
XHeptane = 0.45
∴ Mole fraction of octane = 0.55 = Xoctane
Total pressure =
= (105 × 0.45) + (45 × 0.55) kPa
= 72.0 KPa
XHeptane = 0.45
∴ Mole fraction of octane = 0.55 = Xoctane
Total pressure =
= (105 × 0.45) + (45 × 0.55) kPa
= 72.0 KPa
Mole fraction of Heptane =
XHeptane = 0.45
∴ Mole fraction of octane = 0.55 = Xoctane
Total pressure =
= (105 × 0.45) + (45 × 0.55) kPa
= 72.0 KPa
Create a free account to view solution
View Solution FreeMore Solution Questions
What is the [OH-] in the solution prepared by mixing 20.0 ml of 0.050 M HCl with 30 ml of 0.10 M Ba(OH)2...Barium ions, CN- and Co2+ form an ionic complex. If that is supposed to be 75% ionised in water with vant Hoff factor (i...The fraction of phenol dimerised in benzene if 20 g of phenol in 1 kg benzene exhibits a freezing point depression of 0....Ratio of of 10g AB2 and 14g A2B per 100g of solvent in their respective, solution (AB2 and A2B both are non-electrolytes...What is the normal freezing point of the solution represented by the phase diagram ?...