Math miscellaneousEasy
Question
If ϖ (≠ 1) is a cube root of unity, and (1 + ϖ)7 = A + B ϖ. Then (A, B) equals
Options
A.(1, 1)
B.(1, 0)
C.(-1, 1)
D.(0, 1)
Solution
1 + ϖ = - ϖ2
(1 + ϖ)7 = (-ϖ2)7 = - ϖ 14 = - ϖ2 = 1 + ϖ = A + Bϖ ⇒ (A, B ) = (1, 1)
(1 + ϖ)7 = (-ϖ2)7 = - ϖ 14 = - ϖ2 = 1 + ϖ = A + Bϖ ⇒ (A, B ) = (1, 1)
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