VectorHard
Question
The vernier of a circular scale is divided in to 30 divisions which coincide against 29 divisions of main scale.What is the least count:-
Options
A.10′
B.0.1′
C.1′
D.30′
Solution
Least count = 1MSD - 1VSD
but 30 VSD = 29 MSD ⇒ VSD =
MSD
Therefore L.C = 1 MSD -
MSD
=
= 1′
but 30 VSD = 29 MSD ⇒ VSD =
MSDTherefore L.C = 1 MSD -
MSD =
= 1′Create a free account to view solution
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