Errors in measurementMedium
Question
The vernier of a circular scale is divided in to 30 divisions which coincide against 29 divisions of main scale.What is the least count:-
Options
A.10′
B.0.1′
C.1′
D.30′
Solution
Least count = 1MSD - 1VSD
but 30 VSD = 29 MSD ⇒ VSD =
MSD
Therefore L.C = 1 MSD -
MSD
=
= 1′
but 30 VSD = 29 MSD ⇒ VSD =
MSDTherefore L.C = 1 MSD -
MSD =
= 1′Create a free account to view solution
View Solution FreeMore Errors in measurement Questions
student performs an experiment for determination of , l ≈ lm, and he commits an error of ᐃl. For T he takes ...The length, breadth and thickness of a strip are (10.0 ± 0.1) cm, (1.00 ± 0.01)cm and (0.100 ± 0.001)cm r...Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of di...A student measure the distance traversed in free of a body, Initially at rest, in a given time. He uses this data to est...Significant figure in 3400 are -...