Errors in measurementEasy
Question
The external and internal radius of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm. The thickness of the wall of the cylinder is :-
Options
A.(0.34 ± 0.02) cm
B.(0.17 ± 0.02) cm
C.(0.17 ± 0.01) cm
D.(0.34 ± 0.01) cm
Solution
Thickness of the wall
= (4.23 ± 0.01) - (3.89 ± 0.01) = (0.34 ± 0.02) cm
= (4.23 ± 0.01) - (3.89 ± 0.01) = (0.34 ± 0.02) cm
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