Errors in measurementMedium
Question
In a vernier calipers, N divisions of the main scale coincide with N + m divisions of the vernier scale. What is the value of m for which the instrument has minimum least count ?
Options
A.1
B.N
C.Infinity
D.N / 2
Solution
L.C. = 1 MSD - 1 VSD but (N) MSD = (N + M)(VSD)
⇒ L.C. = 1 MSD -
MSD
=
MSD
For minimum least count, m should be minimum so m = 1
⇒ L.C. = 1 MSD -
MSD=
MSDFor minimum least count, m should be minimum so m = 1
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