ParabolaHard
Question
The equation of a straight line passing through the point (3, 6) and cutting the curve y = √x orthogonally is -
Options
A.4x + y - 18 = 0
B.x + y - 9 = 0
C.4x - y - 6 = 0
D.none
Solution
The curve y = √x is the part of curve y2 = x
equation of normal at P
y + tx =
...... (1)Since line cut the curve orthogonally
so equation (1) will passes (3, 6)
6 + 3t =
t3 - 10t - 24 = 0
solving we get t = 4
so equation of line which passes (3, 6) is
y + 4x = 18
Create a free account to view solution
View Solution FreeMore Parabola Questions
Directer of a parabola is x + y = 2. If it’s focus is origin, then talus rectum of the parabola is equal to -...The locus of the mid point of the line segment joining the focus to a moving point on the parabola y2 = 4ax is another p...Let L be a normal to the parabola y2 = 4x. If L passes through the point (9, 6), then L is given by...The co-ordinates of a point on the parabola y2 = 8x whose focal distance is 4 is...Let the image of the parabola $x^2 = 4y$ in the line $x - y = 1$ be $(y + a)^2 = b(x - c)$, where $a, b, c \in \mathbb{N...