ParabolaHard
Question
The equation of a straight line passing through the point (3, 6) and cutting the curve y = √x orthogonally is -
Options
A.4x + y - 18 = 0
B.x + y - 9 = 0
C.4x - y - 6 = 0
D.none
Solution
The curve y = √x is the part of curve y2 = x
equation of normal at P
y + tx =
...... (1)Since line cut the curve orthogonally
so equation (1) will passes (3, 6)
6 + 3t =
t3 - 10t - 24 = 0
solving we get t = 4
so equation of line which passes (3, 6) is
y + 4x = 18
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