ParabolaHard
Question
The equation of a straight line passing through the point (3, 6) and cutting the curve y = √x orthogonally is -
Options
A.4x + y - 18 = 0
B.x + y - 9 = 0
C.4x - y - 6 = 0
D.none
Solution
The curve y = √x is the part of curve y2 = x
equation of normal at P
y + tx =
...... (1)Since line cut the curve orthogonally
so equation (1) will passes (3, 6)
6 + 3t =
t3 - 10t - 24 = 0
solving we get t = 4
so equation of line which passes (3, 6) is
y + 4x = 18
Create a free account to view solution
View Solution FreeMore Parabola Questions
PQ is a normal chord of the parabola y2 = 4ax at P, A being the vertex of the parabola. Through P a line is drawn parall...If the chord joining the points $P_1(x_1, y_1)$ and $P_2(x_2, y_2)$ on the parabola $y^2 = 12x$ subtends a right angle a...Locus of the intersection of the tangents at the ends of the normal chords of the parabola y2 = 4ax is -...The centre of the circle passing through the point (0, 1) and touching the curve y = x2 at (2, 4) is...The area bounded by the parabola x2 = 8y & the line x - 2y + 8 = 0 is -...