Nuclear Physics and RadioactivityHard
Question
The wavelength of line for an element of atomic number 43 is . Then the wavelength of for an element of atomic number 29 is : -
Options
A.(43/29) λ
B.(42/28) λ
C.(9/4) λ
D.(4/9) λ
Solution
= R (Z - 1)2 
For Kα line, n1 = 1, n2 = 2
= R(43 - 1)2
= R (42)2 
...............(i)and
= R(29 - 1)2 = R (42)2 ................(ii)Dividing eq. (i) by (ii), we get
⇒ λ′ = 
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