Nuclear Physics and RadioactivityHard

Question

The wavelength of  line for an element of atomic number 43 is . Then the wavelength of for an element of atomic number 29 is : -

Options

A.(43/29) λ
B.(42/28) λ
C.(9/4) λ
D.(4/9) λ

Solution

= R (Z - 1)2 
For Kα line, n1 = 1, n2 = 2
= R(43 - 1)2 = R  (42)2 ...............(i)
and
= R(29 - 1)2 = R  (42)2 ................(ii)
Dividing eq. (i) by (ii), we get ⇒ λ′ = λ

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