Nuclear Physics and RadioactivityHard
Question
An atom $\ _{3}^{8}X$ is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by :
Options
A.$250\%$
B.$150\%$
C.
$125\%$
D.$900\%$
Solution
Sol. Surface area $x \propto A^{2/3}$
$${X_{i} = 8^{2/3}\text{ }K = 4\text{ }K }{X_{f} = (8 + 10 + 9)^{2/3}\text{ }K = 9\text{ }K }$$% increase in surface area of nucleus
$$x_{i} = \frac{9K - 4K}{4K} \times 100 = 125\%$$
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A radioactive element X disintegrates into a stable element Y with half life 2 year. A fresh sample of X is available at...A radioactive material decays by simultaneous emission of two particles with respective half−lives 1620 and 810 ye...How much energy is released when 2 mole of U235 is fissioned :-...Which one is correct about fission :-...1.5 mW of 400 nm light is directed at a photo electron cell. If 0.10% of the incident photons produce photo electrons, t...