Nuclear Physics and RadioactivityHard
Question
An atom $\ _{3}^{8}X$ is bombarded by shower of fundamental particles and in 10 s this atom absorbed 10 electrons, 10 protons and 9 neutrons. The percentage growth in the surface area of the nucleons is recorded by :
Options
A.$250\%$
B.$150\%$
C.
$125\%$
D.$900\%$
Solution
Sol. Surface area $x \propto A^{2/3}$
$${X_{i} = 8^{2/3}\text{ }K = 4\text{ }K }{X_{f} = (8 + 10 + 9)^{2/3}\text{ }K = 9\text{ }K }$$% increase in surface area of nucleus
$$x_{i} = \frac{9K - 4K}{4K} \times 100 = 125\%$$
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