Nuclear Physics and RadioactivityHard
Question
The number of photons (λ = 6630
) that strike per second on a a totally reflecting screen (as screen in figure), so that a force of 1N is exerted on the screen, is approximately
) that strike per second on a a totally reflecting screen (as screen in figure), so that a force of 1N is exerted on the screen, is approximately Options
A.1023
B.1027
C.1025
D.1026
Solution
F = 
⇒ F = 
⇒ F = 2npsin θ [n = number of photon]
⇒ 1N = 2(n)
,sin 30o n = 1027
⇒ F = ⇒ F = 2npsin θ [n = number of photon]
⇒ 1N = 2(n)
,sin 30o n = 1027Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
The following nuclear reaction is :-4 1H1 → 2He4 + 2 1e0 + 2ν + 26Mev...A radioactive nucleus decay as follows :- X X1 X2 X3 X4, if the atomic number and the mass number of X are 72 and 180 th...Which of the following is/are evidence(s) for the existence of neutrons in an atom ?...The essential distinction between X-rays and γ-rays is that the γ - rays :...Starting with a sample of pure 66Cu, 7/8 of it decays into Zn in 15 minutes. The corresponding half-life is...