Nuclear Physics and RadioactivityHard
Question
The number of photons (λ = 6630
) that strike per second on a a totally reflecting screen (as screen in figure), so that a force of 1N is exerted on the screen, is approximately
) that strike per second on a a totally reflecting screen (as screen in figure), so that a force of 1N is exerted on the screen, is approximately Options
A.1023
B.1027
C.1025
D.1026
Solution
F = 
⇒ F = 
⇒ F = 2npsin θ [n = number of photon]
⇒ 1N = 2(n)
,sin 30o n = 1027
⇒ F = ⇒ F = 2npsin θ [n = number of photon]
⇒ 1N = 2(n)
,sin 30o n = 1027Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
A radioactive element X converts into another stable element Y. Half-life of X is 2h. Initially, only X is present after...Which one of the following is true in photoelectric emission...In nuclear fission the percentage of mass converted into energy is about:-...When a hydrogen atom is excited from ground state to first excited state, then...If Nt = Noe−λt, then number of disintegrated atoms between t1 to t2 ( t2 > t1) will be :-...