Nuclear Physics and RadioactivityHard
Question
A sample of radioactive material decays simultaneously by two processes A and B with half lives
and
hr respectively. For first half hr it decays with the process A, next one hr with the process B and for further half an hour with both A and B. If originally there were N0 nuclei, find the number of nuclei after 2 hr of such decay.
Options
A.
B.
C.
D.
Solution
TA =
hr, TB =
e; TA+B = 
so, first
hr, = 1 half lives (by A)
next 1 hr = 4 half lives (by B)
next
hr = 3 half lives (by A + B)
thus N =
(∵ Total eight half lives)
so, first
next 1 hr = 4 half lives (by B)
next
thus N =
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
The basic structural unit of silicates is :-...The Energy is liberated when two deutron nuclei combines to form a nucleus of helium, because the mass of helium nucleus...Count rate measured for a radioactive sample is 128 counts/s at t = 0 and 32 counts/s at t = 1 hr. What will be count ra...The probability that a certain radioactive atom would get disintegrated in a time equal to the mean life of the radioact...Which of the following statement is wrong ?...